Oracle® Database SQL Reference 10g Release 2 (10.2) Part Number B14200-02 |
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PDF · Mobi · ePub |
XMLAgg
is an aggregate function. It takes a collection of XML fragments and returns an aggregated XML document. Any arguments that return null are dropped from the result.
XMLAgg
is similar to SYS_XMLAgg
except that XMLAgg
returns a collection of nodes but it does not accept formatting using the XMLFormat
object. Also, XMLAgg
does not enclose the output in an element tag as does SYS_XMLAgg
.
Within the order_by_clause
, Oracle Database does not interpret number literals as column positions, as it does in other uses of this clause, but simply as number literals.
The following example produces a Department
element containing Employee
elements with employee job ID and last name as the contents of the elements:
SELECT XMLELEMENT("Department", XMLAGG(XMLELEMENT("Employee", e.job_id||' '||e.last_name) ORDER BY last_name)) as "Dept_list" FROM employees e WHERE e.department_id = 30; Dept_list ------------------------------------------------------------- <Department> <Employee>PU_CLERK Baida</Employee> <Employee>PU_CLERK Colmenares</Employee> <Employee>PU_CLERK Himuro</Employee> <Employee>PU_CLERK Khoo</Employee> <Employee>PU_MAN Raphaely</Employee> <Employee>PU_CLERK Tobias</Employee> </Department>
The result is a single row, because XMLAgg
aggregates the rows. You can use the GROUP
BY
clause to group the returned set of rows into multiple groups:
SELECT XMLELEMENT("Department", XMLAGG(XMLELEMENT("Employee", e.job_id||' '||e.last_name))) AS "Dept_list" FROM employees e GROUP BY e.department_id; Dept_list --------------------------------------------------------- <Department> <Employee>AD_ASST Whalen</Employee> </Department> <Department> <Employee>MK_MAN Hartstein</Employee> <Employee>MK_REP Fay</Employee> </Department> <Department> <Employee>PU_MAN Raphaely</Employee> <Employee>PU_CLERK Khoo</Employee> <Employee>PU_CLERK Tobias</Employee> <Employee>PU_CLERK Baida</Employee> <Employee>PU_CLERK Colmenares</Employee> <Employee>PU_CLERK Himuro</Employee> </Department> . . .